Splitting large text file into smaller text files by line numbers using Python

匿名 (未验证) 提交于 2019-12-03 02:31:01

问题:

I have a text file say really_big_file.txt that contains:

line 1 line 2 line 3 line 4 ... line 99999 line 100000 

I would like to write a Python script that divides really_big_file.txt into smaller files with 300 lines each. For example, small_file_300.txt to have lines 1-300, small_file_600 to have lines 301-600, and so on until there are enough small files made to contain all the lines from the big file.

I would appreciate any suggestions on the easiest way to accomplish this using Python

回答1:

Using itertools grouper recipe:

from itertools import izip_longest  def grouper(n, iterable, fillvalue=None):     "Collect data into fixed-length chunks or blocks"     # grouper(3, 'ABCDEFG', 'x') --> ABC DEF Gxx     args = [iter(iterable)] * n     return izip_longest(fillvalue=fillvalue, *args)  n = 300  with open('really_big_file.txt') as f:     for i, g in enumerate(grouper(n, f, fillvalue=''), 1):         with open('small_file_{0}'.format(i * n), 'w') as fout:             fout.writelines(g) 

The advantage of this method as opposed to storing each line in a list, is that it works with iterables, line by line, so it doesn't have to store each small_file into memory at once.

Note that the last file in this case will be small_file_100200 but will only go until line 100000. This happens because fillvalue='', meaning I write out nothing to the file when I don't have any more lines left to write because a group size doesn't divide equally. You can fix this by writing to a temp file and then renaming it after instead of naming it first like I have. Here's how that can be done.

import os, tempfile  with open('really_big_file.txt') as f:     for i, g in enumerate(grouper(n, f, fillvalue=None)):         with tempfile.NamedTemporaryFile('w', delete=False) as fout:             for j, line in enumerate(g, 1): # count number of lines in group                 if line is None:                     j -= 1 # don't count this line                     break                 fout.write(line)         os.rename(fout.name, 'small_file_{0}.txt'.format(i * n + j)) 

This time the fillvalue=None and I go through each line checking for None, when it occurs, I know the process has finished so I subtract 1 from j to not count the filler and then write the file.



回答2:

lines_per_file = 300 smallfile = None with open('really_big_file.txt') as bigfile:     for lineno, line in enumerate(bigfile):         if lineno % lines_per_file == 0:             if smallfile:                 smallfile.close()             small_filename = 'small_file_{}.txt'.format(lineno + lines_per_file)             smallfile = open(small_filename, "w")         smallfile.write(line)     if smallfile:         smallfile.close() 


回答3:

import csv import os import re  MAX_CHUNKS = 300   def writeRow(idr, row):     with open("file_%d.csv" % idr, 'ab') as file:         writer = csv.writer(file, delimiter=',', quotechar='\"', quoting=csv.QUOTE_ALL)         writer.writerow(row)  def cleanup():     for f in os.listdir("."):         if re.search("file_.*", f):             os.remove(os.path.join(".", f))  def main():     cleanup()     with open("large_file.csv", 'rb') as results:         r = csv.reader(results, delimiter=',', quotechar='\"')         idr = 1         for i, x in enumerate(r):             temp = i + 1             if not (temp % (MAX_CHUNKS + 1)):                 idr += 1             writeRow(idr, x)  if __name__ == "__main__": main() 


回答4:

I do this a more understandable way and using less short cuts in order to give you a further understanding of how and why this works. Previous answers work, but if you are not familiar with certain built-in-functions, you will not understand what the function is doing.

Because you posted no code I decided to do it this way since you could be unfamiliar with things other than basic python syntax given that the way you phrased the question made it seem as though you did not try nor had any clue as how to approach the question

Here are the steps to do this in basic python:

First you should read your file into a list for safekeeping:

my_file = 'really_big_file.txt' hold_lines = [] with open(my_file,'r') as text_file:     for row in text_file:         hold_lines.append(row) 

Second, you need to set up a way of creating the new files by name! I would suggest a loop along with a couple counters:

outer_count = 1 line_count = 0 sorting = True while sorting:     count = 0     increment = (outer_count-1) * 300     left = len(hold_lines) - increment     file_name = "small_file_" + str(outer_count * 300) + ".txt" 

Third, inside that loop you need some nested loops that will save the correct rows into an array:

hold_new_lines = []     if left 

Last thing, again in your first loop you need to write the new file and add your last counter increment so your loop will go through again and write a new file

outer_count += 1 with open(file_name,'w') as next_file:     for row in hold_new_lines:         next_file.write(row) 

note: if the number of lines is not divisible by 300, the last file will have a name that does not correspond to the last file line.

It is important to understand why these loops work. You have it set so that on the next loop, the name of the file that you write changes because you have the name dependent on a changing variable. This is a very useful scripting tool for file accessing, opening, writing, organizing etc.

In case you could not follow what was in what loop, here is the entirety of the function:

my_file = 'really_big_file.txt' sorting = True hold_lines = [] with open(my_file,'r') as text_file:     for row in text_file:         hold_lines.append(row) outer_count = 1 line_count = 0 while sorting:     count = 0     increment = (outer_count-1) * 300     left = len(hold_lines) - increment     file_name = "small_file_" + str(outer_count * 300) + ".txt"     hold_new_lines = []     if left 


回答5:

lines_per_file = 300  # Lines on each small file lines = []  # Stores lines not yet written on a small file lines_counter = 0  # Same as len(lines) created_files = 0  # Counting how many small files have been created  with open('really_big_file.txt') as big_file:     for line in big_file:  # Go throught the whole big file         lines.append(line)         lines_counter += 1         if lines_counter == lines_per_file:             idx = lines_per_file * (created_files + 1)             with open('small_file_%s.txt' % idx, 'w') as small_file:                 # Write all lines on small file                 small_file.write('\n'.join(stored_lines))             lines = []  # Reset variables             lines_counter = 0             created_files += 1  # One more small file has been created     # After for-loop has finished     if lines_counter:  # There are still some lines not written on a file?         idx = lines_per_file * (created_files + 1)         with open('small_file_%s.txt' % idx, 'w') as small_file:             # Write them on a last small file             small_file.write('n'.join(stored_lines))         created_files += 1  print '%s small files (with %s lines each) were created.' % (created_files,                                                              lines_per_file) 


标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!