可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试):
问题:
i'm trying to use php to split a string into array components using either " or ' as the delimiter. i just want to split by the outermost string. here are four examples and the desired result for each:
$pattern = "?????"; $str = "the cat 'sat on' the mat"; $res = preg_split($pattern, $str); print_r($res); /*output: Array ( [0] => the cat [1] => 'sat on' [2] => the mat )*/ $str = "the cat \"sat on\" the mat"; $res = preg_split($pattern, $str); print_r($res); /*output: Array ( [0] => the cat [1] => "sat on" [2] => the mat )*/ $str = "the \"cat 'sat' on\" the mat"; $res = preg_split($pattern, $str); print_r($res); /*output: Array ( [0] => the [1] => "cat 'sat' on" [2] => the mat )*/ $str = "the 'cat \"sat\" on' the mat 'when \"it\" was' seventeen"; $res = preg_split($pattern, $str); print_r($res); /*output: Array ( [0] => the [1] => 'cat "sat" on' [2] => the mat [3] => 'when "it" was' [4] => seventeen )*/
as you can see i only want to split by the outermost quotation, and i want to ignore any quotations within quotations.
the closest i have come up with for $pattern is
$pattern = "/((?P<quot>['\"])[^(?P=quot)]*?(?P=quot))/";
but obviously this is not working.
回答1:
You can use preg_split with the PREG_SPLIT_DELIM_CAPTURE
$str = "the 'cat \"sat\" on' the mat the \"cat 'sat' on\" the mat"; $match = preg_split("/('[^']*'|\"[^\"]*\")/U", $str, null, PREG_SPLIT_DELIM_CAPTURE); print_r($match);
回答2:
You can use just preg_match for this:
$str = "the \"cat 'sat' on\" the mat"; $pattern = '/^([^\'"]*)(([\'"]).*\3)(.*)$/'; if (preg_match($pattern, $str, $matches)) { printf("[initial] => %s\n[quoted] => %s\n[end] => %s\n", $matches[1], $matches[2], $matches[4] ); }
This prints:
[initial] => the [quoted] => "cat 'sat' on" [end] => the mat
Here is an explanation of the regex:
/^([^\'"]*) => put the initial bit until the first quote (either single or double) in the first captured group(([\'"]).*\3) => capture in \2 the text corresponding from the initial quote (either single or double) (that is captured in \3) until the closing quote (that must be the same type as the opening quote, hence the \3). The fact that the regexp is greedy by nature helps to get from the first quote to the last one, regardless of how many quotes are inside.(.*)$/ => Capture until the end in \4
回答3:
Yet another solution using preg_replace_callback
$result1 = array(); function parser($p) { global $result1; $result1[] = $p[0]; return "|"; // temporary delimiter } $str = "the 'cat \"sat\" on' the mat 'when \"it\" was' seventeen"; $str = preg_replace_callback("/(['\"]).*\\1/U", "parser", $str); $result2 = explode("|",$str); // using temporary delimiter
Now you can zip those arrays using array_map
$result = array(); function zipper($a,$b) { global $result; if($a) $result[] = $a; if($b) $result[] = $b; } array_map("zipper",$result2,$result1); print_r($result);
And the result is
[0] => the [1] => 'cat "sat" on' [2] => the mat [3] => 'when "it" was' [4] => seventeen
Note: I'd would be probably better to create a class doing this feat, so the global variables can be avoided.
回答4:
You can use back references and ungreedy modifier in preg_match_all
$str = "the 'cat \"sat\" on' the mat 'when \"it\" was' seventeen"; preg_match_all("/(['\"])(.*)\\1/U", $str, $match); print_r($match[0]);
Now you have your outermost quotation parts
[0] => 'cat "sat" on' [1] => 'when "it" was'
And you can find the rest of the string with substr and strpos (kind of blackbox solution)
$a = $b = 0; $result = array(); foreach($match[0] as $part) { $b = strpos($str,$part); $result[] = substr($str,$a,$b-$a); $result[] = $part; $a = $b+strlen($part); } $result[] = substr($str,$a); print_r($result);
Here is the result
[0] => the [1] => 'cat "sat" on' [2] => the mat [3] => 'when "it" was' [4] => seventeen
Just strip eventual empty heading/trailing element if the quotation is at the very beginning/end of the string.
