I have a class that is currently extending Activity and I have methods like findViewById, ArrayAdapter etc. I want to turn it into an independent class but all the above methods become undefined. What is the problem? Shouldn't importing the classes be enough? For eg, I import android.view.View for findViewById but it still makes no difference. Please advise.
问题:
回答1:
you should pass the instance of your Activity to your Second Class on the constructor like this :
In your Activity
Instanciate your Class like this :
MyClass instance = new MyClass(this);
And in your second Class , the constructor will be like this :
public class MyClass { public Activity activity; //.... other attributes public MyClass( Activity _activity){ this.activity = _activity; //other initializations... } }
and then when you want to use the findViewById()
method , you can do like this :
EditText txt = (EditText)this.activity.findViewById(R.id.txt);
回答2:
if you want to call any function that belongs to Activity
then only thing you need to have is context of the Activity
.
eg.
class A extends Activity{ Context ctx; void oncreate(Bundle b) ctx = this; B bob = new B(ctx); } }
Here is class B.
Class B { B(Activity a) { a.anyFunctionOfActivity(); } }
回答3:
findViewById is non-static public method of the Activity
Class ,so it only be available for a Activity
object. Therefore, import android.view.View
and android.app.Activity
won't make it available. To make it available, you could pass around a Actvity
object - usually a this
point in your activity. However, notice that you should always update your View in the UI thread.
回答4:
Please try the following:
public static View getLayoutByRes(@LayoutRes int layoutRes,@Nullable ViewGroup viewGroup) { final LayoutInflater factory = getSystemService(Context.LAYOUT_INFLATER_SERVICE); return factory.inflate(layoutRes, viewGroup); } TextView tv = (TextView) getLayoutByRes(R.layout.xxx ,Null).findViewById(R.id.editd);