How to create listeners with javascript

问题:

I need to create a main class animal, then have two sub classes inherit properties from animal which are cat and dog, then I was to make multiple objects (multiple cat's and dog's) inherit from the class cat and dog (I read it's not really a class but it behaves as a class).

The multiple objects (cat1, mycat, tomcat, dog1, mydog, topdog) need to be able to talk and listen to each other. When talking I would have them just alert or print a text line. What I am having trouble with is the listening part. I want the individual myDog to print out "dog heard cat" when myCat makes a sound. This is the code I have so far.

var animal = function (name, sound, listen) {     var f = 0;     this.name = name; // this.prop means prop is public var.     this.sound = sound;     this.listen = listen;     this.makesound = function () {         alert(this.sound);     }     this.listen = function () {         alert(this.name + "heard that");     }     return this; };  /*--------------- inheritance -----------------------------------*/ var cat = function () {      this.name = name;     this.sound = 'meow';     return this; }; cat.prototype = new animal();  function dog(name) {     dog.sound = 'woof';     dog.name = name;     return this; }; dog.prototype = new animal();  /*-------- different kinda dogs/cats ----------------------------*/ var myCat = new cat(); var myDog = new dog(); var tomCat = new cat(); var bigDog = new dog(); /*-----------------------*/ 

I think I'm supposed to use an if statement, I heard I can use like a if (callback) callback{} but my attempts to implement something like that are failing. I'm BRAND new to javascript only been learning it last couple days. Any help or assistance would be really appreciated.

回答1:

This is how I would do it... I'd set those who are listening. listening is an optional parameter when you create a new object. You can also change those who are listening after creation using setListening. listening in this case will just be an array of objects that have a name property.

Also, I fixed some issues, you either didn't have "name" or weren't setting it in any case.

http://jsfiddle.net/n9xCM/

var animal = function (name, sound, listening) {     var f = 0;     this.name = name; // this.prop means prop is public var.     this.sound = sound;     this.listening = listening;     this.makesound = function () {         alert(this.sound);         this.listen();     }     this.setListening = function (listening) {         this.listening = listening;     }     this.listen = function () {         console.log("in listen ("+this.listening.length+")");         for (var i = 0; i < this.listening.length; i++) {             alert(this.listening[i].name + " heard that");         }     }     return this; };  /*--------------- inheritance -----------------------------------*/ var cat = function (name, listening) {     this.name = name;     this.listening = listening;     this.sound = 'meow';     return this; }; cat.prototype = new animal();  function dog(name, listening) {     this.sound = 'woof';     this.listening = listening;     this.name = name;     return this; }; dog.prototype = new animal();  /*-------- different kinda dogs/cats ----------------------------*/ var myDog = new dog("mydog"); var myCat = new cat("mycat", [myDog]); var bigDog = new dog("buster"); var tomCat = new cat("tommy", [bigDog]); myCat.makesound(); //meow - mydog heard that bigDog.setListening([myDog, myCat, tomCat]); bigDog.makesound(); //woof - mydog/mycat/tommy heard that  /*-----------------------*/ 

回答2:

There is a pattern for that, the Observer pattern. When an animal makes a sound the other animals get notified (they 'listen' to it).

this.listen = function(otherAnimal)  {     alert(this.name + "heard " + otherAnimal.name); } 

So the makeSound function has to call the listen method of all animals that can 'listen' to the sound. To do that it has to know those, i.e. have a list of them, or if it's only one, have a reference to that.

function makeSound() {     alert(this.sound);      for (var i = 0; i < this.listening.length; i++) {         this.listening[i].listen(this);     }     // OR this.listening.listen(this); if it can only be one other animal } 

listening could come in as an argument via constructor or method.

P.S.: Never use an if or switch to make decisions based on a type. That's what OOP is for.

文章来源: How to create listeners with javascript