python语法糖

反转字符串

>>> a =  "codementor" >>> print "Reverse is",a[::-1] 

矩阵转置

>>> mat = [[1, 2, 3], [4, 5, 6]] >>> zip(*mat) [(1, 4), (2, 5), (3, 6)] 

列表转字符串

a = ["Code", "mentor", "Python", "Developer"] >>> print " ".join(a) 

列表拉链

>>> for x, y in zip(list1,list2): ...    print x, y ... a p b q c r d s 

多重嵌套列表转单一列表

>>> import itertools  >>> list(itertools.chain.from_iterable(a)) [1, 2, 3, 4, 5, 6] 

检查两个单词是否是相互颠倒的

from collections import Counter def is_anagram(str1, str2):      return Counter(str1) == Counter(str2) >>> is_anagram('abcd','dbca') True >>> is_anagram('abcd','dbaa') False 

一行代码获取用户输入并放到列表中

>>> result = map(lambda x:int(x) ,raw_input().split()) 1 2 3 4 >>> result [1, 2, 3, 4] 

文章来源: python语法糖